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ACK expiration timer (line 1). The receiver may keep on processing incoming DATA packets without producing an ACK response for as long as a MaxDeferTime period, provided that additional DATA segments arrive within a avgPktInt time frame. If either the MaxDeferTime or the ACK Timer expire, then a cumulative ACK is produced and sent to the sender. Note that no limit is enforced on the number of ACK packets to delay as in the case of delayed ACKs (Section 10.4.2). Experimentation on static string topologies in reference 5 has revealed a 5 25% throughput increase when this method is employed on a Reno (presumably) agent when compared to simply deploying delayed ACKs. However, although the changes proposed in TCP-ADA are end-to-end and con ned to a single layer, objections may be raised on its feasibility as a general solution for

if ( found == true )

Although use of the binary relational operators, such as the less-than or inequality operator, is straightforward, there is one potential pitfall we must be aware of: The order of evaluation of the left and right operands is deliberately left undefined by both the C and the C++ Standards and must therefore not contain order dependencies For example, in the following

// oops! language does not define order of evaluation if ( ia[ index++ ] < ia[ index ] ) // swap elements

the programmer presumes that the left operand is evaluated first and that therefore ia[0] is compared to be less than ia[1] The language, however, does not guarantee a left-to-right evaluation order; an implementation may in fact evaluate the right-hand operand first, in which case ia[0] is compared to itself and ia[1] is never evaluated One safe and portable reimplementation looks like this:

s'(i)(n+1..0) c'(i)(n+1..0) Y(n 1..0)

1: 2: 3: 4: 5: 6: 7: 8: 9: 10: 11: 12: 13:

if ( ia[ index ] < ia[ index+1 ] ) // swap elements ++index;

A second potential pitfall is the following Our intention is to determine whether ival, jval, and kval are each unique values Do you see what's wrong

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (146 / 1065) [2001-3-29 11:32:04]

// oops! this does not determine if the 3 values are unequal if ( ival != jval != kval ) // do something

lastPktArr 0, avgPktInt 0 = 0.8, = 1.2 MaxDeferTime = 500ms if lastPktArr = 0 then lastPktArr now else avgpktArr avgPktInt + (1 ) (now lastPktArr) lastPktArr now end if if MaxDeferTimer not pending then Schedule MaxDeferTimer for MaxDeferTime end if Reschedule ACK timer for avgPktInt

As we've implemented it, the associated values 0, 1, and 0 cause the expression to evaluate as true The reason is that the left operand of the second inequality expression is the true/false result of the first that is, kval is tested for inequality against the promoted integer values of 0 or 1 To accomplish our test, we might rewrite the expression as follows:

Exercise 44 Which, if any, of the following are likely to be incorrect or not portable Why How might each be corrected (Note that the type of the object(s) is not significant in these examples)

(a) ptr->ival != 0 (b) ival != jval < kval (c) ptr != 0 && *ptr++ (d) ival++ && ival (e) vec[ ival++ ] <= vec[ ival ];

Exercise 45 The order of evaluation of the binary operators is left undefined to permit the compiler freedom to provide an optimal implementation The trade-off is between an efficient implementation and a potential pitfall in the use of the language by the programmer Do you consider that an acceptable trade-off Why or why not

MANETs Speci cally, the performance advantages offered by the technique have not been con rmed in dynamic MANETs, which may generate much different results to those exhibited in static topologies [7] There is also little discussion with respect to the choice of the and parameters, which de ne the weighing constants for the average interarrival ACK time and the wait factor for the ACK timer, respectively Finally, the issue of overhead in terms of processing capacity of implementing a ne-grained ACK response timer per TCP connection is not addressed in the original work Overall, the method can be considered a variation on the theme of dynamically adaptive ACKs, as described in more detail in Section 1042 Dynamic Delayed ACK (DDA).

An initialization provides an object with a first value For example:

s'(i+1)(n+1..0)

int ival = 1024; int *pi = 0;

An assignment, in contrast, overwrites an object's current value with a new value For example:

ival = 2048; pi = &ival;

Initialization and assignment are sometimes confused because both of them use the same operator (=) An object can be initialized only once: at the time of its definition An object can be assigned multiple times throughout the program