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by the sender). Such a delay in ACK transmission could be as high as approximately 500 ms (the maximum recommended time length of the expiration timer [37]). This undesirable situation is depicted in Figure 10.4. To facilitate the delay in ACK production in a dynamic way, Altman and Jim nez e [6] identify that the above two factors, namely path length and packets-in- ight, cannot be known at the receiving end without utilizing extra signaling. Hence, the technique is applied in a generally useful fashion, which means that it is designed to provide modest returns in the case of short paths but reasonable gains in throughput otherwise. Speci cally, a delay coef cient parameter, d, is introduced to the receiving end of a TCP connection where it de nes the number of ACKs the receiver should delay before responding to the reception of DATA segments. Hence, if d = 2 the scheme becomes equivalent to the standard delayed ACKs mechanism described in Section 10.4.2. Then, three thresholds are de ned, l1 , l2 , l3 according to the sequence number N of the received DATA segment.1 . For N < l1 , d = 1, for l1 N < l2 , d = 2, for l2 N < l3 , d = 3 and for l3 N, d = 4. The set of threshold values used in the subsequent evaluation is {l1 , l2 , l3 } = {2, 5, 9}. The principal notion is to increase the delay coef cient as more and more segments appear in order. It is hoped that during that time period the number of packets-in- ight will gradually increase and the increase in the delay coef cient will, thus, have a meaningful and positive impact. The algorithm is outlined in Algorithm 2.

ival = 0;

ival = 314159;

Figure 13.16. The combinational circuit (Figure 13.15) implements the circuit of Table 13.2. An additional (not represented) p-bit subtractor generates Q q_pos 2 q_neg. Another additional (not represented) (n 1)-bit adder generates r( p) s0 ( p) c0 (p), that is, the decoded value of the nal remainder. Furthermore, a correction circuit, similar to that of Figure 13.6, is necessary if the condition sign(R) sign(X) is to hold. The cost and computation time of the carry-save basic cell of Figure 13.14 are given by Cdivision

is 3, both of type int Because of this, an assignment can appear as a subexpression For example, the following while loop

extern char next_char(); int main() { char ch = next_char(); while ( ch != '\n' ) { // do something ch = next_char(); } // }

1 The initial sequence number (ISN) for each endpoint is negotiated by TCP during the three-way handshake

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (149 / 1065) [2001-3-29 11:32:04]

can be rewritten as follows:

extern char next_char(); int main() { char ch; while (( ch = next_char() ) != '\n' ) { // do something } // }

The additional parentheses are necessary because of the lower precedence of the assignment operator to that of inequality Precedence determines the order of evaluation within an expression, with higher operators being evaluated first Without parentheses, the inequality test

next_char() != '\n'

upon connection establishment and is 32-bits wide [18]. In this context, the sequence number is assumed to be 0 initially without loss of generality (the l thresholds may be presented as full-sized segment offsets, in bytes, to the initial negotiated ISN as appropriate).

is evaluated first, and ch is then assigned the true or false value of whether the result of next_char() is equal to the newline character clearly not what we intended! (We look at precedence in detail in Section 413) Similarly, assignment operators can be concatenated provided that each of the operands being assigned is of the same general data type For example, in the following

int main() { int ival, jval; ival = jval = 0; // ok: each assigned 0 // }

step (n)

ival and jval are each assigned 0 However, the following is illegal, because ival and pval are objects of different types, although 0 is a valid value that can be assigned to either:

int main() { int ival; int *pval; ival = pval = 0; // error: not the same types // }

1: 2: 3: 4: 5: 6: 7: 8: 9: 10: 11: 12:

The following may or may not be legal; however, it does not serve as a definition of both ival and jval:

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (150 / 1065) [2001-3-29 11:32:04]

int main() { // int ival = jval = 0; // may or may not be legal // }

The example is legal only if jval has been previously defined and is of the appropriate type to be assigned zero In that case, ival is initialized to the result of assigning jval a value of 0, which itself is 0 In order for it to define both objects, it must be rewritten as follows:

d 1 l1 = 2, l2 = 5, l3 = 9 N ISN(0) if N < l1 then d 1 else if l1 N < l2 then d 2 else if l2 N < l3 then d 3 else if l3 N then d 4 end if

int main() { // ok: defines ival and jval int ival = 0, jval = 0; // }

int arraySum( int ia[], int sz ) { int sum = 0; for ( int i = 0; i < sz; ++i ) sum = sum + ia[ i ]; return sum; }

For that reason, a set of compound assignment operators is provided For example, the preceding function can be rewritten using the compound assignment-plus operator:

n:CAND2 Ccarry-save adder (n 2)